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200111511441431 is a prime number
BaseRepresentation
bin101101100000000000010111…
…100011100001000000010111
3222020112110210022002012210202
4231200000113203201000113
5202212111333412111211
61545333543110411115
760102402542034662
oct5540002743410027
9866473708065722
10200111511441431
11588418a7348807
121a53ab50360a9b
138787585955a15
14375b63d8486d9
15182055dbe153b
hexb600178e1017

200111511441431 has 2 divisors, whose sum is σ = 200111511441432. Its totient is φ = 200111511441430.

The previous prime is 200111511441421. The next prime is 200111511441451. The reversal of 200111511441431 is 134144115111002.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200111511441431 is a prime.

It is a super-2 number, since 2×2001115114414312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 200111511441394 and 200111511441403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200111511441421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100055755720715 + 100055755720716.

It is an arithmetic number, because the mean of its divisors is an integer number (100055755720716).

Almost surely, 2200111511441431 is an apocalyptic number.

200111511441431 is a deficient number, since it is larger than the sum of its proper divisors (1).

200111511441431 is an equidigital number, since it uses as much as digits as its factorization.

200111511441431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1920, while the sum is 29.

Adding to 200111511441431 its reverse (134144115111002), we get a palindrome (334255626552433).

The spelling of 200111511441431 in words is "two hundred trillion, one hundred eleven billion, five hundred eleven million, four hundred forty-one thousand, four hundred thirty-one".