Base | Representation |
---|---|
bin | 101101100000000000010111… |
… | …100011100001000000101011 |
3 | 222020112110210022002012211111 |
4 | 231200000113203201000223 |
5 | 202212111333412111301 |
6 | 1545333543110411151 |
7 | 60102402542035021 |
oct | 5540002743410053 |
9 | 866473708065744 |
10 | 200111511441451 |
11 | 588418a7348825 |
12 | 1a53ab50360ab7 |
13 | 8787585955a2c |
14 | 375b63d848711 |
15 | 182055dbe1551 |
hex | b600178e102b |
200111511441451 has 2 divisors, whose sum is σ = 200111511441452. Its totient is φ = 200111511441450.
The previous prime is 200111511441431. The next prime is 200111511441467. The reversal of 200111511441451 is 154144115111002.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200111511441451 - 27 = 200111511441323 is a prime.
It is a super-2 number, since 2×2001115114414512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (200111511441421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100055755720725 + 100055755720726.
It is an arithmetic number, because the mean of its divisors is an integer number (100055755720726).
Almost surely, 2200111511441451 is an apocalyptic number.
200111511441451 is a deficient number, since it is larger than the sum of its proper divisors (1).
200111511441451 is an equidigital number, since it uses as much as digits as its factorization.
200111511441451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3200, while the sum is 31.
Adding to 200111511441451 its reverse (154144115111002), we get a palindrome (354255626552453).
The spelling of 200111511441451 in words is "two hundred trillion, one hundred eleven billion, five hundred eleven million, four hundred forty-one thousand, four hundred fifty-one".
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