Base | Representation |
---|---|
bin | 1001000110011001110101… |
… | …11110001110100010110101 |
3 | 2121212001111212022110011102 |
4 | 10203030322332032202311 |
5 | 10110331010424214333 |
6 | 110321012045415445 |
7 | 4133523142444256 |
oct | 443147276164265 |
9 | 77761455273142 |
10 | 20011242023093 |
11 | 64157a1480412 |
12 | 22b239056a585 |
13 | b2208a3b9cc9 |
14 | 4d279932cb2d |
15 | 24a811cd0ae8 |
hex | 12333af8e8b5 |
20011242023093 has 2 divisors, whose sum is σ = 20011242023094. Its totient is φ = 20011242023092.
The previous prime is 20011242023063. The next prime is 20011242023117. The reversal of 20011242023093 is 39032024211002.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18490060200049 + 1521181823044 = 4300007^2 + 1233362^2 .
It is a cyclic number.
It is not a de Polignac number, because 20011242023093 - 212 = 20011242018997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20011242023063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005621011546 + 10005621011547.
It is an arithmetic number, because the mean of its divisors is an integer number (10005621011547).
Almost surely, 220011242023093 is an apocalyptic number.
It is an amenable number.
20011242023093 is a deficient number, since it is larger than the sum of its proper divisors (1).
20011242023093 is an equidigital number, since it uses as much as digits as its factorization.
20011242023093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 20011242023093 its reverse (39032024211002), we get a palindrome (59043266234095).
The spelling of 20011242023093 in words is "twenty trillion, eleven billion, two hundred forty-two million, twenty-three thousand, ninety-three".
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