Base | Representation |
---|---|
bin | 10010101000110001… |
… | …000110100010111101 |
3 | 1220122121211001020101 |
4 | 102220301012202331 |
5 | 311440344011331 |
6 | 13105411521101 |
7 | 1305620233255 |
oct | 225061064275 |
9 | 56577731211 |
10 | 20011313341 |
11 | 8539956998 |
12 | 3a658b9191 |
13 | 1b6bb39216 |
14 | d7b9cc965 |
15 | 7c1c53061 |
hex | 4a8c468bd |
20011313341 has 2 divisors, whose sum is σ = 20011313342. Its totient is φ = 20011313340.
The previous prime is 20011313339. The next prime is 20011313351. The reversal of 20011313341 is 14331311002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12028605625 + 7982707716 = 109675^2 + 89346^2 .
It is a cyclic number.
It is not a de Polignac number, because 20011313341 - 21 = 20011313339 is a prime.
Together with 20011313339, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20011313351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005656670 + 10005656671.
It is an arithmetic number, because the mean of its divisors is an integer number (10005656671).
Almost surely, 220011313341 is an apocalyptic number.
It is an amenable number.
20011313341 is a deficient number, since it is larger than the sum of its proper divisors (1).
20011313341 is an equidigital number, since it uses as much as digits as its factorization.
20011313341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 20011313341 its reverse (14331311002), we get a palindrome (34342624343).
The spelling of 20011313341 in words is "twenty billion, eleven million, three hundred thirteen thousand, three hundred forty-one".
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