Base | Representation |
---|---|
bin | 101101100000000001111101… |
… | …100101000001100110100010 |
3 | 222020112122012120220010221120 |
4 | 231200001331211001212202 |
5 | 202212123340104104442 |
6 | 1545334425013433110 |
7 | 60102463135021314 |
oct | 5540017545014642 |
9 | 866478176803846 |
10 | 200113223113122 |
11 | 588425a5563010 |
12 | 1a53b34963b796 |
13 | 878779945a9c7 |
14 | 375b762ccb7b4 |
15 | 182060e0ed4ec |
hex | b6007d9419a2 |
200113223113122 has 32 divisors (see below), whose sum is σ = 451666208911680. Its totient is φ = 58549323376320.
The previous prime is 200113223113087. The next prime is 200113223113207. The reversal of 200113223113122 is 221311322311002.
It is a junction number, because it is equal to n+sod(n) for n = 200113223113092 and 200113223113101.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52276179673 + ... + 52276183500.
It is an arithmetic number, because the mean of its divisors is an integer number (14114569028490).
Almost surely, 2200113223113122 is an apocalyptic number.
200113223113122 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
200113223113122 is an abundant number, since it is smaller than the sum of its proper divisors (251552985798558).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200113223113122 is a wasteful number, since it uses less digits than its factorization.
200113223113122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104552363218.
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 200113223113122 its reverse (221311322311002), we get a palindrome (421424545424124).
The spelling of 200113223113122 in words is "two hundred trillion, one hundred thirteen billion, two hundred twenty-three million, one hundred thirteen thousand, one hundred twenty-two".
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