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200114141 is a prime number
BaseRepresentation
bin10111110110101…
…11111111011101
3111221112211222212
423323113333131
5402212123031
631505050205
74646641103
oct1373277735
9457484885
10200114141
11a2a60797
1257026965
13325c7246
141c811c73
151287d12b
hexbed7fdd

200114141 has 2 divisors, whose sum is σ = 200114142. Its totient is φ = 200114140.

The previous prime is 200114129. The next prime is 200114171. The reversal of 200114141 is 141411002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 154281241 + 45832900 = 12421^2 + 6770^2 .

It is a cyclic number.

It is not a de Polignac number, because 200114141 - 26 = 200114077 is a prime.

It is a super-3 number, since 3×2001141413 (a number of 26 digits) contains 333 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200114171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100057070 + 100057071.

It is an arithmetic number, because the mean of its divisors is an integer number (100057071).

Almost surely, 2200114141 is an apocalyptic number.

It is an amenable number.

200114141 is a deficient number, since it is larger than the sum of its proper divisors (1).

200114141 is an equidigital number, since it uses as much as digits as its factorization.

200114141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 14.

The square root of 200114141 is about 14146.1705418816. The cubic root of 200114141 is about 584.9147765885.

Adding to 200114141 its reverse (141411002), we get a palindrome (341525143).

The spelling of 200114141 in words is "two hundred million, one hundred fourteen thousand, one hundred forty-one".