Base | Representation |
---|---|
bin | 1001000110011011010001… |
… | …10011101011110011001101 |
3 | 2121212010111110022002122021 |
4 | 10203031220303223303031 |
5 | 10110334044304330102 |
6 | 110321220235450141 |
7 | 4133551200646315 |
oct | 443155063536315 |
9 | 77763443262567 |
10 | 20012011011277 |
11 | 641605655a63a |
12 | 22b2565bb6951 |
13 | b221808024bc |
14 | 4d282d504445 |
15 | 24a85957e137 |
hex | 123368cebccd |
20012011011277 has 2 divisors, whose sum is σ = 20012011011278. Its totient is φ = 20012011011276.
The previous prime is 20012011011143. The next prime is 20012011011301. The reversal of 20012011011277 is 77211011021002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13363601451876 + 6648409559401 = 3655626^2 + 2578451^2 .
It is a cyclic number.
It is not a de Polignac number, because 20012011011277 - 211 = 20012011009229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20012011011677) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006005505638 + 10006005505639.
It is an arithmetic number, because the mean of its divisors is an integer number (10006005505639).
Almost surely, 220012011011277 is an apocalyptic number.
It is an amenable number.
20012011011277 is a deficient number, since it is larger than the sum of its proper divisors (1).
20012011011277 is an equidigital number, since it uses as much as digits as its factorization.
20012011011277 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 392, while the sum is 25.
Adding to 20012011011277 its reverse (77211011021002), we get a palindrome (97223022032279).
The spelling of 20012011011277 in words is "twenty trillion, twelve billion, eleven million, eleven thousand, two hundred seventy-seven".
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