Base | Representation |
---|---|
bin | 1001000110011011010001… |
… | …10100011100110011011001 |
3 | 2121212010111110200021222012 |
4 | 10203031220310130303121 |
5 | 10110334044332240433 |
6 | 110321220244035305 |
7 | 4133551202443433 |
oct | 443155064346331 |
9 | 77763443607865 |
10 | 20012011211993 |
11 | 6416056687419 |
12 | 22b2566092b35 |
13 | b22180872978 |
14 | 4d282d557653 |
15 | 24a8595bd848 |
hex | 123368d1ccd9 |
20012011211993 has 2 divisors, whose sum is σ = 20012011211994. Its totient is φ = 20012011211992.
The previous prime is 20012011211947. The next prime is 20012011212047. The reversal of 20012011211993 is 39911211021002.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14209823846464 + 5802187365529 = 3769592^2 + 2408773^2 .
It is a cyclic number.
It is not a de Polignac number, because 20012011211993 - 240 = 18912499584217 is a prime.
It is not a weakly prime, because it can be changed into another prime (20012011216993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006005605996 + 10006005605997.
It is an arithmetic number, because the mean of its divisors is an integer number (10006005605997).
Almost surely, 220012011211993 is an apocalyptic number.
It is an amenable number.
20012011211993 is a deficient number, since it is larger than the sum of its proper divisors (1).
20012011211993 is an equidigital number, since it uses as much as digits as its factorization.
20012011211993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 32.
Adding to 20012011211993 its reverse (39911211021002), we get a palindrome (59923222232995).
The spelling of 20012011211993 in words is "twenty trillion, twelve billion, eleven million, two hundred eleven thousand, nine hundred ninety-three".
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