Base | Representation |
---|---|
bin | 101101100000001001010100… |
… | …010010000001110101110110 |
3 | 222020120101120221122211110121 |
4 | 231200021110102001311312 |
5 | 202212241023232431402 |
6 | 1545342212355442154 |
7 | 60103162626123331 |
oct | 5540112422016566 |
9 | 866511527584417 |
10 | 200121120202102 |
11 | 58845988230930 |
12 | 1a5409922b635a |
13 | 878845757b318 |
14 | 375bcb1a47618 |
15 | 182092256b837 |
hex | b60254481d76 |
200121120202102 has 64 divisors (see below), whose sum is σ = 330058933747200. Its totient is φ = 90246844800000.
The previous prime is 200121120201929. The next prime is 200121120202109. The reversal of 200121120202102 is 201202021121002.
It is a happy number.
It is a super-3 number, since 3×2001211202021023 (a number of 44 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200121120202109) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13927275174 + ... + 13927289542.
It is an arithmetic number, because the mean of its divisors is an integer number (5157170839800).
Almost surely, 2200121120202102 is an apocalyptic number.
200121120202102 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
200121120202102 is a deficient number, since it is larger than the sum of its proper divisors (129937813545098).
200121120202102 is a wasteful number, since it uses less digits than its factorization.
200121120202102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19573.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 200121120202102 its reverse (201202021121002), we get a palindrome (401323141323104).
The spelling of 200121120202102 in words is "two hundred trillion, one hundred twenty-one billion, one hundred twenty million, two hundred two thousand, one hundred two".
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