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2001212111141 is a prime number
BaseRepresentation
bin11101000111110001100…
…010010111100100100101
321002022110220122110212022
4131013301202113210211
5230241440300024031
64131202200432525
7264403621164545
oct35076142274445
97068426573768
102001212111141
11701789079931
12283a21a78745
131169377092b9
146cc05853325
15370c960b97b
hex1d1f1897925

2001212111141 has 2 divisors, whose sum is σ = 2001212111142. Its totient is φ = 2001212111140.

The previous prime is 2001212111111. The next prime is 2001212111207. The reversal of 2001212111141 is 1411112121002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1998488315041 + 2723796100 = 1413679^2 + 52190^2 .

It is a cyclic number.

It is not a de Polignac number, because 2001212111141 - 26 = 2001212111077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2001212111111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000606055570 + 1000606055571.

It is an arithmetic number, because the mean of its divisors is an integer number (1000606055571).

Almost surely, 22001212111141 is an apocalyptic number.

It is an amenable number.

2001212111141 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001212111141 is an equidigital number, since it uses as much as digits as its factorization.

2001212111141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 2001212111141 its reverse (1411112121002), we get a palindrome (3412324232143).

The spelling of 2001212111141 in words is "two trillion, one billion, two hundred twelve million, one hundred eleven thousand, one hundred forty-one".