Base | Representation |
---|---|
bin | 11101000111110010000… |
… | …000011101011101100101 |
3 | 21002022111110111020210001 |
4 | 131013302000131131211 |
5 | 230241444304441324 |
6 | 4131203041501301 |
7 | 264404045221126 |
oct | 35076200353545 |
9 | 7068443436701 |
10 | 2001219999589 |
11 | 701792577608 |
12 | 283a24641831 |
13 | 11693923ba15 |
14 | 6cc0690804d |
15 | 370ca168e44 |
hex | 1d1f201d765 |
2001219999589 has 2 divisors, whose sum is σ = 2001219999590. Its totient is φ = 2001219999588.
The previous prime is 2001219999553. The next prime is 2001219999599. The reversal of 2001219999589 is 9859999121002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1884464526564 + 116755473025 = 1372758^2 + 341695^2 .
It is a cyclic number.
It is not a de Polignac number, because 2001219999589 - 215 = 2001219966821 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2001219999589.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001219999599) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000609999794 + 1000609999795.
It is an arithmetic number, because the mean of its divisors is an integer number (1000609999795).
Almost surely, 22001219999589 is an apocalyptic number.
It is an amenable number.
2001219999589 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001219999589 is an equidigital number, since it uses as much as digits as its factorization.
2001219999589 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9447840, while the sum is 64.
The spelling of 2001219999589 in words is "two trillion, one billion, two hundred nineteen million, nine hundred ninety-nine thousand, five hundred eighty-nine".
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