200122423117 has 2 divisors, whose sum is σ = 200122423118. Its totient is φ = 200122423116.

The previous prime is 200122423051. The next prime is 200122423187. The reversal of 200122423117 is 711324221002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 187202463561 + 12919959556 = 432669^2 + 113666^2 .

It is a cyclic number.

It is not a de Polignac number, because 200122423117 - 2⁷ = 200122422989 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 200122423091 and 200122423100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200122423187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100061211558 + 100061211559.

It is an arithmetic number, because the mean of its divisors is an integer number (100061211559).

Almost surely, 2^200122423117 is an apocalyptic number.

It is an amenable number.

200122423117 is a deficient number, since it is larger than the sum of its proper divisors (1).

200122423117 is an equidigital number, since it uses as much as digits as its factorization.

200122423117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 200122423117 its reverse (711324221002), we get a palindrome (911446644119).

The spelling of 200122423117 in words is "two hundred billion, one hundred twenty-two million, four hundred twenty-three thousand, one hundred seventeen".