Base | Representation |
---|---|
bin | 101101100000001011000110… |
… | …010011010001100010010111 |
3 | 222020120120112021011200210221 |
4 | 231200023012103101202113 |
5 | 202212303432440144114 |
6 | 1545343130252255211 |
7 | 60103261214552065 |
oct | 5540130623214227 |
9 | 866516467150727 |
10 | 200123033131159 |
11 | 5884677a007836 |
12 | 1a541226a71507 |
13 | 87886a098a9c8 |
14 | 375c013b19035 |
15 | 18209d5480524 |
hex | b602c64d1897 |
200123033131159 has 2 divisors, whose sum is σ = 200123033131160. Its totient is φ = 200123033131158.
The previous prime is 200123033131139. The next prime is 200123033131223. The reversal of 200123033131159 is 951131330321002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200123033131159 - 217 = 200123033000087 is a prime.
It is a super-2 number, since 2×2001230331311592 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200123033131139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100061516565579 + 100061516565580.
It is an arithmetic number, because the mean of its divisors is an integer number (100061516565580).
Almost surely, 2200123033131159 is an apocalyptic number.
200123033131159 is a deficient number, since it is larger than the sum of its proper divisors (1).
200123033131159 is an equidigital number, since it uses as much as digits as its factorization.
200123033131159 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14580, while the sum is 34.
The spelling of 200123033131159 in words is "two hundred trillion, one hundred twenty-three billion, thirty-three million, one hundred thirty-one thousand, one hundred fifty-nine".
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