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2001244853 is a prime number
BaseRepresentation
bin111011101001000…
…1001001010110101
312011110200202211202
41313102021022311
513044304313403
6530325342245
7100410205046
oct16722111265
95143622752
102001244853
11937717973
1247a267985
1325b7c1b6a
1414db008cd
15baa5b688
hex774892b5

2001244853 has 2 divisors, whose sum is σ = 2001244854. Its totient is φ = 2001244852.

The previous prime is 2001244813. The next prime is 2001244859. The reversal of 2001244853 is 3584421002.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1996123684 + 5121169 = 44678^2 + 2263^2 .

It is a cyclic number.

It is not a de Polignac number, because 2001244853 - 214 = 2001228469 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2001244859) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000622426 + 1000622427.

It is an arithmetic number, because the mean of its divisors is an integer number (1000622427).

Almost surely, 22001244853 is an apocalyptic number.

It is an amenable number.

2001244853 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001244853 is an equidigital number, since it uses as much as digits as its factorization.

2001244853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7680, while the sum is 29.

The square root of 2001244853 is about 44735.2752646052. The cubic root of 2001244853 is about 1260.1823984287.

Adding to 2001244853 its reverse (3584421002), we get a palindrome (5585665855).

The spelling of 2001244853 in words is "two billion, one million, two hundred forty-four thousand, eight hundred fifty-three".