Base | Representation |
---|---|
bin | 10010101000111000… |
… | …011101110000101001 |
3 | 1220122202110002211021 |
4 | 102220320131300221 |
5 | 311441342242213 |
6 | 13105521132441 |
7 | 1305642522331 |
oct | 225070356051 |
9 | 56582402737 |
10 | 20013243433 |
11 | 853aa55007 |
12 | 3a6648a121 |
13 | 1b6c3638a1 |
14 | d7bd720c1 |
15 | 7c1ed4d8d |
hex | 4a8e1dc29 |
20013243433 has 2 divisors, whose sum is σ = 20013243434. Its totient is φ = 20013243432.
The previous prime is 20013243431. The next prime is 20013243463. The reversal of 20013243433 is 33434231002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11614803984 + 8398439449 = 107772^2 + 91643^2 .
It is a cyclic number.
It is not a de Polignac number, because 20013243433 - 21 = 20013243431 is a prime.
Together with 20013243431, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 20013243398 and 20013243407.
It is not a weakly prime, because it can be changed into another prime (20013243431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006621716 + 10006621717.
It is an arithmetic number, because the mean of its divisors is an integer number (10006621717).
Almost surely, 220013243433 is an apocalyptic number.
It is an amenable number.
20013243433 is a deficient number, since it is larger than the sum of its proper divisors (1).
20013243433 is an equidigital number, since it uses as much as digits as its factorization.
20013243433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 20013243433 its reverse (33434231002), we get a palindrome (53447474435).
The spelling of 20013243433 in words is "twenty billion, thirteen million, two hundred forty-three thousand, four hundred thirty-three".
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