Base | Representation |
---|---|
bin | 1011101001100101101… |
… | …1010000010100101011 |
3 | 201010121021112012101102 |
4 | 2322121123100110223 |
5 | 11234342443220121 |
6 | 231535541312015 |
7 | 20313501433352 |
oct | 2723133202453 |
9 | 633537465342 |
10 | 200142554411 |
11 | 77975288468 |
12 | 3295740560b |
13 | 15b47a120b7 |
14 | 9988dcc999 |
15 | 5315c3290b |
hex | 2e996d052b |
200142554411 has 2 divisors, whose sum is σ = 200142554412. Its totient is φ = 200142554410.
The previous prime is 200142554363. The next prime is 200142554413. The reversal of 200142554411 is 114455241002.
It is a happy number.
200142554411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200142554411 - 226 = 200075445547 is a prime.
Together with 200142554413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (200142554413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100071277205 + 100071277206.
It is an arithmetic number, because the mean of its divisors is an integer number (100071277206).
Almost surely, 2200142554411 is an apocalyptic number.
200142554411 is a deficient number, since it is larger than the sum of its proper divisors (1).
200142554411 is an equidigital number, since it uses as much as digits as its factorization.
200142554411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6400, while the sum is 29.
Adding to 200142554411 its reverse (114455241002), we get a palindrome (314597795413).
The spelling of 200142554411 in words is "two hundred billion, one hundred forty-two million, five hundred fifty-four thousand, four hundred eleven".
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