Base | Representation |
---|---|
bin | 11101001000000011111… |
… | …010100011101001011111 |
3 | 21002100021101211022012221 |
4 | 131020003322203221133 |
5 | 230243103213120301 |
6 | 4131252533210211 |
7 | 264414354022312 |
oct | 35100372435137 |
9 | 7070241738187 |
10 | 2001520441951 |
11 | 701927123388 |
12 | 283aa9190967 |
13 | 116986562c74 |
14 | 6cc34794979 |
15 | 370e6713da1 |
hex | 1d203ea3a5f |
2001520441951 has 2 divisors, whose sum is σ = 2001520441952. Its totient is φ = 2001520441950.
The previous prime is 2001520441939. The next prime is 2001520442027. The reversal of 2001520441951 is 1591440251002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2001520441951 - 29 = 2001520441439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001521441951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000760220975 + 1000760220976.
It is an arithmetic number, because the mean of its divisors is an integer number (1000760220976).
Almost surely, 22001520441951 is an apocalyptic number.
2001520441951 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001520441951 is an equidigital number, since it uses as much as digits as its factorization.
2001520441951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 34.
Adding to 2001520441951 its reverse (1591440251002), we get a palindrome (3592960692953).
The spelling of 2001520441951 in words is "two trillion, one billion, five hundred twenty million, four hundred forty-one thousand, nine hundred fifty-one".
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