Base | Representation |
---|---|
bin | 10010101001000000… |
… | …011100110000110101 |
3 | 1220122220101102222022 |
4 | 102221000130300311 |
5 | 311442411232001 |
6 | 13110034042525 |
7 | 1305666360506 |
oct | 225100346065 |
9 | 56586342868 |
10 | 20015336501 |
11 | 8541154616 |
12 | 3a67119445 |
13 | 1b6c9174a4 |
14 | d7c358bad |
15 | 7c229a11b |
hex | 4a901cc35 |
20015336501 has 2 divisors, whose sum is σ = 20015336502. Its totient is φ = 20015336500.
The previous prime is 20015336479. The next prime is 20015336503. The reversal of 20015336501 is 10563351002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13880374225 + 6134962276 = 117815^2 + 78326^2 .
It is a cyclic number.
It is not a de Polignac number, because 20015336501 - 218 = 20015074357 is a prime.
It is a super-2 number, since 2×200153365012 (a number of 21 digits) contains 22 as substring.
Together with 20015336503, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20015336503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10007668250 + 10007668251.
It is an arithmetic number, because the mean of its divisors is an integer number (10007668251).
Almost surely, 220015336501 is an apocalyptic number.
It is an amenable number.
20015336501 is a deficient number, since it is larger than the sum of its proper divisors (1).
20015336501 is an equidigital number, since it uses as much as digits as its factorization.
20015336501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 26.
Adding to 20015336501 its reverse (10563351002), we get a palindrome (30578687503).
The spelling of 20015336501 in words is "twenty billion, fifteen million, three hundred thirty-six thousand, five hundred one".
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