Base | Representation |
---|---|
bin | 101101100001011100010001… |
… | …111011000100010111101111 |
3 | 222020212220112011021101212011 |
4 | 231201130101323010113233 |
5 | 202220220443001400421 |
6 | 1545451144030422051 |
7 | 60112465266116644 |
oct | 5541342173042757 |
9 | 866786464241764 |
10 | 200210201200111 |
11 | 5887a740121143 |
12 | 1a5560b3361927 |
13 | 8793982b82b2b |
14 | 376232287ddcb |
15 | 1822dd7db64e1 |
hex | b61711ec45ef |
200210201200111 has 2 divisors, whose sum is σ = 200210201200112. Its totient is φ = 200210201200110.
The previous prime is 200210201200099. The next prime is 200210201200123. The reversal of 200210201200111 is 111002102012002.
It is a balanced prime because it is at equal distance from previous prime (200210201200099) and next prime (200210201200123).
It is a cyclic number.
It is not a de Polignac number, because 200210201200111 - 215 = 200210201167343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200210201200091 and 200210201200100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200210201200211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105100600055 + 100105100600056.
It is an arithmetic number, because the mean of its divisors is an integer number (100105100600056).
Almost surely, 2200210201200111 is an apocalyptic number.
200210201200111 is a deficient number, since it is larger than the sum of its proper divisors (1).
200210201200111 is an equidigital number, since it uses as much as digits as its factorization.
200210201200111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 200210201200111 its reverse (111002102012002), we get a palindrome (311212303212113).
The spelling of 200210201200111 in words is "two hundred trillion, two hundred ten billion, two hundred one million, two hundred thousand, one hundred eleven".
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