Base | Representation |
---|---|
bin | 1011101001110110000… |
… | …0010111001100011111 |
3 | 201010210001022201000121 |
4 | 2322131200113030133 |
5 | 11240013004032033 |
6 | 231550424335411 |
7 | 20315262303415 |
oct | 2723540271437 |
9 | 633701281017 |
10 | 200211002143 |
11 | 779aa989239 |
12 | 32976314567 |
13 | 15b58c59209 |
14 | 99941292b5 |
15 | 531bc5362d |
hex | 2e9d81731f |
200211002143 has 2 divisors, whose sum is σ = 200211002144. Its totient is φ = 200211002142.
The previous prime is 200211002083. The next prime is 200211002153. The reversal of 200211002143 is 341200112002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200211002143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200211002153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105501071 + 100105501072.
It is an arithmetic number, because the mean of its divisors is an integer number (100105501072).
Almost surely, 2200211002143 is an apocalyptic number.
200211002143 is a deficient number, since it is larger than the sum of its proper divisors (1).
200211002143 is an equidigital number, since it uses as much as digits as its factorization.
200211002143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 200211002143 its reverse (341200112002), we get a palindrome (541411114145).
The spelling of 200211002143 in words is "two hundred billion, two hundred eleven million, two thousand, one hundred forty-three".
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