Base | Representation |
---|---|
bin | 1001000110101100011001… |
… | …01100010101101100101111 |
3 | 2121220000020001122111211011 |
4 | 10203112030230111230233 |
5 | 10111011410432000421 |
6 | 110325340320010051 |
7 | 4134325034400505 |
oct | 443261454255457 |
9 | 77800201574734 |
10 | 20021203000111 |
11 | 6419a43161925 |
12 | 22b42b0460927 |
13 | b22cb6c93551 |
14 | 4d3062214675 |
15 | 24abe65314e1 |
hex | 12358cb15b2f |
20021203000111 has 2 divisors, whose sum is σ = 20021203000112. Its totient is φ = 20021203000110.
The previous prime is 20021203000069. The next prime is 20021203000133. The reversal of 20021203000111 is 11100030212002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20021203000111 - 217 = 20021202869039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20021203000091 and 20021203000100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20021206000111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010601500055 + 10010601500056.
It is an arithmetic number, because the mean of its divisors is an integer number (10010601500056).
Almost surely, 220021203000111 is an apocalyptic number.
20021203000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021203000111 is an equidigital number, since it uses as much as digits as its factorization.
20021203000111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 20021203000111 its reverse (11100030212002), we get a palindrome (31121233212113).
The spelling of 20021203000111 in words is "twenty trillion, twenty-one billion, two hundred three million, one hundred eleven", and thus it is an aban number.
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