Base | Representation |
---|---|
bin | 101101100001011110000011… |
… | …001010100111000111100011 |
3 | 222020220002102120021022112211 |
4 | 231201132003022213013203 |
5 | 202220233340340200003 |
6 | 1545452100340102551 |
7 | 60112563336031456 |
oct | 5541360312470743 |
9 | 866802376238484 |
10 | 200212101100003 |
11 | 58880525609043 |
12 | 1a556543694a57 |
13 | 8793bc667cc55 |
14 | 3762462d1d49d |
15 | 1822e99aa496d |
hex | b617832a71e3 |
200212101100003 has 2 divisors, whose sum is σ = 200212101100004. Its totient is φ = 200212101100002.
The previous prime is 200212101100001. The next prime is 200212101100019. The reversal of 200212101100003 is 300001101212002.
200212101100003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200212101100003 - 21 = 200212101100001 is a prime.
Together with 200212101100001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (200212101100001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100106050550001 + 100106050550002.
It is an arithmetic number, because the mean of its divisors is an integer number (100106050550002).
Almost surely, 2200212101100003 is an apocalyptic number.
200212101100003 is a deficient number, since it is larger than the sum of its proper divisors (1).
200212101100003 is an equidigital number, since it uses as much as digits as its factorization.
200212101100003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 200212101100003 its reverse (300001101212002), we get a palindrome (500213202312005).
The spelling of 200212101100003 in words is "two hundred trillion, two hundred twelve billion, one hundred one million, one hundred thousand, three".
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