Base | Representation |
---|---|
bin | 101101100001100101100110… |
… | …100111101100101000101111 |
3 | 222020220212100211120211101222 |
4 | 231201211212213230220233 |
5 | 202220401443300320421 |
6 | 1545455521243253555 |
7 | 60113301335412431 |
oct | 5541454647545057 |
9 | 866825324524358 |
10 | 200220212120111 |
11 | 58883a08014547 |
12 | 1a558027b1a2bb |
13 | 87948b9bc4831 |
14 | 37629d2246651 |
15 | 18232c1bcecab |
hex | b619669eca2f |
200220212120111 has 2 divisors, whose sum is σ = 200220212120112. Its totient is φ = 200220212120110.
The previous prime is 200220212120077. The next prime is 200220212120129. The reversal of 200220212120111 is 111021212022002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200220212120111 - 210 = 200220212119087 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 200220212120111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200220212120141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100110106060055 + 100110106060056.
It is an arithmetic number, because the mean of its divisors is an integer number (100110106060056).
Almost surely, 2200220212120111 is an apocalyptic number.
200220212120111 is a deficient number, since it is larger than the sum of its proper divisors (1).
200220212120111 is an equidigital number, since it uses as much as digits as its factorization.
200220212120111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 200220212120111 its reverse (111021212022002), we get a palindrome (311241424142113).
The spelling of 200220212120111 in words is "two hundred trillion, two hundred twenty billion, two hundred twelve million, one hundred twenty thousand, one hundred eleven".
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