Base | Representation |
---|---|
bin | 1001000110101110011101… |
… | …01011010010010001011111 |
3 | 2121220010002012200221212212 |
4 | 10203113032223102101133 |
5 | 10111021142331121231 |
6 | 110330042223151035 |
7 | 4134364336042343 |
oct | 443271653222137 |
9 | 77803065627785 |
10 | 20022310020191 |
11 | 641a461031456 |
12 | 22b455b14547b |
13 | b2313243160b |
14 | 4d312925d623 |
15 | 24ac5d80242b |
hex | 1235cead245f |
20022310020191 has 2 divisors, whose sum is σ = 20022310020192. Its totient is φ = 20022310020190.
The previous prime is 20022310020043. The next prime is 20022310020277. The reversal of 20022310020191 is 19102001322002.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20022310020191 is a prime.
It is a super-3 number, since 3×200223100201913 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20022310020991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10011155010095 + 10011155010096.
It is an arithmetic number, because the mean of its divisors is an integer number (10011155010096).
Almost surely, 220022310020191 is an apocalyptic number.
20022310020191 is a deficient number, since it is larger than the sum of its proper divisors (1).
20022310020191 is an equidigital number, since it uses as much as digits as its factorization.
20022310020191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 20022310020191 its reverse (19102001322002), we get a palindrome (39124311342193).
The spelling of 20022310020191 in words is "twenty trillion, twenty-two billion, three hundred ten million, twenty thousand, one hundred ninety-one".
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