Base | Representation |
---|---|
bin | 11101001000110011000… |
… | …111000000000010111101 |
3 | 21002102022120201110112212 |
4 | 131020303013000002331 |
5 | 230301213412430044 |
6 | 4131503300110205 |
7 | 264443110106414 |
oct | 35106307000275 |
9 | 7072276643485 |
10 | 2002312233149 |
11 | 7021a3067878 |
12 | 28408a395365 |
13 | 116a81600677 |
14 | 6ccab9c447b |
15 | 37140eb8a9e |
hex | 1d2331c00bd |
2002312233149 has 2 divisors, whose sum is σ = 2002312233150. Its totient is φ = 2002312233148.
The previous prime is 2002312233121. The next prime is 2002312233161. The reversal of 2002312233149 is 9413322132002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1984055359225 + 18256873924 = 1408565^2 + 135118^2 .
It is a cyclic number.
It is not a de Polignac number, because 2002312233149 - 212 = 2002312229053 is a prime.
It is a super-3 number, since 3×20023122331493 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2002312233949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001156116574 + 1001156116575.
It is an arithmetic number, because the mean of its divisors is an integer number (1001156116575).
Almost surely, 22002312233149 is an apocalyptic number.
It is an amenable number.
2002312233149 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002312233149 is an equidigital number, since it uses as much as digits as its factorization.
2002312233149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 32.
The spelling of 2002312233149 in words is "two trillion, two billion, three hundred twelve million, two hundred thirty-three thousand, one hundred forty-nine".
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