Base | Representation |
---|---|
bin | 11101001000110100001… |
… | …111011001111000011101 |
3 | 21002102100220102202110221 |
4 | 131020310033121320131 |
5 | 230301233242311331 |
6 | 4131505215001341 |
7 | 264443430330304 |
oct | 35106417317035 |
9 | 7072326382427 |
10 | 2002331213341 |
11 | 702202850988 |
12 | 284094809251 |
13 | 116a85517854 |
14 | 6ccb032543b |
15 | 371429b7711 |
hex | 1d2343d9e1d |
2002331213341 has 2 divisors, whose sum is σ = 2002331213342. Its totient is φ = 2002331213340.
The previous prime is 2002331213269. The next prime is 2002331213383. The reversal of 2002331213341 is 1433121332002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1012883229241 + 989447984100 = 1006421^2 + 994710^2 .
It is a cyclic number.
It is not a de Polignac number, because 2002331213341 - 215 = 2002331180573 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2002331216341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001165606670 + 1001165606671.
It is an arithmetic number, because the mean of its divisors is an integer number (1001165606671).
Almost surely, 22002331213341 is an apocalyptic number.
It is an amenable number.
2002331213341 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002331213341 is an equidigital number, since it uses as much as digits as its factorization.
2002331213341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 2002331213341 its reverse (1433121332002), we get a palindrome (3435452545343).
The spelling of 2002331213341 in words is "two trillion, two billion, three hundred thirty-one million, two hundred thirteen thousand, three hundred forty-one".
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