Base | Representation |
---|---|
bin | 11101001001011100110… |
… | …001110001000111001111 |
3 | 21002111010022011020202020 |
4 | 131021130301301013033 |
5 | 230304131343410111 |
6 | 4132100511501223 |
7 | 264466326134424 |
oct | 35113461610717 |
9 | 7074108136666 |
10 | 2003011310031 |
11 | 702521736666 |
12 | 284244527813 |
13 | 116b633a8824 |
14 | 6cd3679bd4b |
15 | 37182557906 |
hex | 1d25cc711cf |
2003011310031 has 64 divisors (see below), whose sum is σ = 2804981114880. Its totient is φ = 1270173864960.
The previous prime is 2003011310029. The next prime is 2003011310071. The reversal of 2003011310031 is 1300131103002.
It is not a de Polignac number, because 2003011310031 - 21 = 2003011310029 is a prime.
It is a super-2 number, since 2×20030113100312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2003011310011) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 811920660 + ... + 811923126.
It is an arithmetic number, because the mean of its divisors is an integer number (43827829920).
Almost surely, 22003011310031 is an apocalyptic number.
2003011310031 is a deficient number, since it is larger than the sum of its proper divisors (801969804849).
2003011310031 is a wasteful number, since it uses less digits than its factorization.
2003011310031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3296.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 2003011310031 its reverse (1300131103002), we get a palindrome (3303142413033).
The spelling of 2003011310031 in words is "two trillion, three billion, eleven million, three hundred ten thousand, thirty-one".
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