Base | Representation |
---|---|
bin | 10010101001111100… |
… | …101100110111101101 |
3 | 1220201000002220010002 |
4 | 102221330230313231 |
5 | 312010432143432 |
6 | 13111400354045 |
7 | 1306250543114 |
oct | 225174546755 |
9 | 56630086102 |
10 | 20031131117 |
11 | 854a062318 |
12 | 3a70475925 |
13 | 1b72c8770a |
14 | d804aac7b |
15 | 7c3869e62 |
hex | 4a9f2cded |
20031131117 has 2 divisors, whose sum is σ = 20031131118. Its totient is φ = 20031131116.
The previous prime is 20031131101. The next prime is 20031131119. The reversal of 20031131117 is 71113113002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16259820196 + 3771310921 = 127514^2 + 61411^2 .
It is a cyclic number.
It is not a de Polignac number, because 20031131117 - 24 = 20031131101 is a prime.
Together with 20031131119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20031131119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10015565558 + 10015565559.
It is an arithmetic number, because the mean of its divisors is an integer number (10015565559).
Almost surely, 220031131117 is an apocalyptic number.
It is an amenable number.
20031131117 is a deficient number, since it is larger than the sum of its proper divisors (1).
20031131117 is an equidigital number, since it uses as much as digits as its factorization.
20031131117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 126, while the sum is 20.
Adding to 20031131117 its reverse (71113113002), we get a palindrome (91144244119).
The spelling of 20031131117 in words is "twenty billion, thirty-one million, one hundred thirty-one thousand, one hundred seventeen".
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