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200312024132111 is a prime number
BaseRepresentation
bin101101100010111011000111…
…000010101110101000001111
3222021020122100101002021200212
4231202323013002232220033
5202223403011134211421
61550010023513313035
760123031456553003
oct5542730702565017
9867218311067625
10200312024132111
1158909941554011
121a57198b70577b
1387a045c251458
143767221a66703
151825897188e5b
hexb62ec70aea0f

200312024132111 has 2 divisors, whose sum is σ = 200312024132112. Its totient is φ = 200312024132110.

The previous prime is 200312024132057. The next prime is 200312024132113. The reversal of 200312024132111 is 111231420213002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 200312024132111 - 238 = 200037146225167 is a prime.

Together with 200312024132113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200312024132113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100156012066055 + 100156012066056.

It is an arithmetic number, because the mean of its divisors is an integer number (100156012066056).

Almost surely, 2200312024132111 is an apocalyptic number.

200312024132111 is a deficient number, since it is larger than the sum of its proper divisors (1).

200312024132111 is an equidigital number, since it uses as much as digits as its factorization.

200312024132111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 200312024132111 its reverse (111231420213002), we get a palindrome (311543444345113).

The spelling of 200312024132111 in words is "two hundred trillion, three hundred twelve billion, twenty-four million, one hundred thirty-two thousand, one hundred eleven".