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200312333113300 = 2252374116321138393
BaseRepresentation
bin101101100010111011011001…
…011101011001011111010100
3222021020200010220111011012121
4231202323121131121133110
5202223404124234111200
61550010114312025324
760123042231056542
oct5542733135313724
9867220126434177
10200312333113300
1158909a8aa02171
121a571a57092244
1387a04ab275165
143767250ad6d92
1518258b436de1a
hexb62ed97597d4

200312333113300 has 288 divisors, whose sum is σ = 462312557852544. Its totient is φ = 75231120384000.

The previous prime is 200312333113229. The next prime is 200312333113313. The reversal of 200312333113300 is 3311333213002.

200312333113300 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 5217398904 + ... + 5217437296.

It is an arithmetic number, because the mean of its divisors is an integer number (1605251936988).

Almost surely, 2200312333113300 is an apocalyptic number.

200312333113300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 200312333113300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (231156278926272).

200312333113300 is an abundant number, since it is smaller than the sum of its proper divisors (262000224739244).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200312333113300 is a wasteful number, since it uses less digits than its factorization.

200312333113300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38859 (or 38852 counting only the distinct ones).

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 200312333113300 its reverse (3311333213002), we get a palindrome (203623666326302).

The spelling of 200312333113300 in words is "two hundred trillion, three hundred twelve billion, three hundred thirty-three million, one hundred thirteen thousand, three hundred".