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2003128445441 is a prime number
BaseRepresentation
bin11101001001100011110…
…000100110101000000001
321002111102110120100022202
4131021203300212220001
5230304401340223231
64132120254242545
7264502250565164
oct35114360465001
97074373510282
102003128445441
11702581871192
122842777b6455
13116b8173b916
146cd4816dadb
153718c9945cb
hex1d263c26a01

2003128445441 has 2 divisors, whose sum is σ = 2003128445442. Its totient is φ = 2003128445440.

The previous prime is 2003128445429. The next prime is 2003128445453. The reversal of 2003128445441 is 1445448213002.

It is a balanced prime because it is at equal distance from previous prime (2003128445429) and next prime (2003128445453).

It can be written as a sum of positive squares in only one way, i.e., 1554859363600 + 448269081841 = 1246940^2 + 669529^2 .

It is a cyclic number.

It is not a de Polignac number, because 2003128445441 - 218 = 2003128183297 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2003128445395 and 2003128445404.

It is not a weakly prime, because it can be changed into another prime (2003128445141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001564222720 + 1001564222721.

It is an arithmetic number, because the mean of its divisors is an integer number (1001564222721).

Almost surely, 22003128445441 is an apocalyptic number.

It is an amenable number.

2003128445441 is a deficient number, since it is larger than the sum of its proper divisors (1).

2003128445441 is an equidigital number, since it uses as much as digits as its factorization.

2003128445441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 122880, while the sum is 38.

The spelling of 2003128445441 in words is "two trillion, three billion, one hundred twenty-eight million, four hundred forty-five thousand, four hundred forty-one".