Base | Representation |
---|---|
bin | 101101100010111100000001… |
… | …111011100110101100001010 |
3 | 222021020201220020011021202010 |
4 | 231202330001323212230022 |
5 | 202223412022100322310 |
6 | 1550010305525320350 |
7 | 60123065114405064 |
oct | 5542740173465412 |
9 | 867221806137663 |
10 | 200313012120330 |
11 | 5890a2a92131aa |
12 | 1a5720065660b6 |
13 | 87a0588b44175 |
14 | 37672b6d68734 |
15 | 1825903c96320 |
hex | b62f01ee6b0a |
200313012120330 has 64 divisors (see below), whose sum is σ = 482250810101760. Its totient is φ = 53250324535296.
The previous prime is 200313012120313. The next prime is 200313012120359. The reversal of 200313012120330 is 33021210313002.
200313012120330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 200313012120297 and 200313012120306.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18251706 + ... + 27087834.
It is an arithmetic number, because the mean of its divisors is an integer number (7535168907840).
Almost surely, 2200313012120330 is an apocalyptic number.
200313012120330 is an abundant number, since it is smaller than the sum of its proper divisors (281937797981430).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200313012120330 is a wasteful number, since it uses less digits than its factorization.
200313012120330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8838495.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 200313012120330 its reverse (33021210313002), we get a palindrome (233334222433332).
The spelling of 200313012120330 in words is "two hundred trillion, three hundred thirteen billion, twelve million, one hundred twenty thousand, three hundred thirty".
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