Base | Representation |
---|---|
bin | 11101001001100011110… |
… | …111011101110000011000 |
3 | 21002111102120221201122111 |
4 | 131021203313131300120 |
5 | 230304402320302440 |
6 | 4132120401002104 |
7 | 264502302066145 |
oct | 35114367356030 |
9 | 7074376851574 |
10 | 2003130244120 |
11 | 70258288a5a5 |
12 | 284278323334 |
13 | 116b81c1b525 |
14 | 6cd484bb3cc |
15 | 3718cbec4ea |
hex | 1d263dddc18 |
2003130244120 has 32 divisors (see below), whose sum is σ = 4511457483120. Its totient is φ = 800467309440.
The previous prime is 2003130244117. The next prime is 2003130244183. The reversal of 2003130244120 is 214420313002.
It is a junction number, because it is equal to n+sod(n) for n = 2003130244091 and 2003130244100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24483282 + ... + 24564961.
Almost surely, 22003130244120 is an apocalyptic number.
2003130244120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2003130244120 is an abundant number, since it is smaller than the sum of its proper divisors (2508327239000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2003130244120 is a wasteful number, since it uses less digits than its factorization.
2003130244120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49049275 (or 49049271 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 2003130244120 its reverse (214420313002), we get a palindrome (2217550557122).
The spelling of 2003130244120 in words is "two trillion, three billion, one hundred thirty million, two hundred forty-four thousand, one hundred twenty".
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