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200313121200000 = 273551249133649
BaseRepresentation
bin101101100010111100001000…
…011011101101011110000000
3222021020202011211102002220220
4231202330020123231132000
5202223412233011400000
61550010324423303040
760123100610514444
oct5542741033553600
9867222154362826
10200313121200000
115890a354846396
121a572036baaa80
1387a05a5616653
1437672c7640824
15182590d6411a0
hexb62f086ed780

200313121200000 has 384 divisors, whose sum is σ = 665597047500000. Its totient is φ = 53373665280000.

The previous prime is 200313121199993. The next prime is 200313121200001. The reversal of 200313121200000 is 2121313002.

It is a tau number, because it is divible by the number of its divisors (384).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200313121200001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1498733176 + ... + 1498866824.

Almost surely, 2200313121200000 is an apocalyptic number.

200313121200000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 200313121200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (332798523750000).

200313121200000 is an abundant number, since it is smaller than the sum of its proper divisors (465283926300000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200313121200000 is an equidigital number, since it uses as much as digits as its factorization.

200313121200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 134940 (or 134908 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 200313121200000 its reverse (2121313002), we get a palindrome (200315242513002).

The spelling of 200313121200000 in words is "two hundred trillion, three hundred thirteen billion, one hundred twenty-one million, two hundred thousand".