Base | Representation |
---|---|
bin | 101101100010111100001000… |
… | …100011110001000110101111 |
3 | 222021020202011222101102002212 |
4 | 231202330020203301012233 |
5 | 202223412234031441142 |
6 | 1550010324540441035 |
7 | 60123100634462144 |
oct | 5542741043610657 |
9 | 867222158342085 |
10 | 200313123312047 |
11 | 5890a355a59189 |
12 | 1a57203784917b |
13 | 87a05a5ba5a95 |
14 | 37672c7a303cb |
15 | 182590d90bd82 |
hex | b62f088f11af |
200313123312047 has 2 divisors, whose sum is σ = 200313123312048. Its totient is φ = 200313123312046.
The previous prime is 200313123311971. The next prime is 200313123312089. The reversal of 200313123312047 is 740213321313002.
200313123312047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200313123312047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200313123312097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100156561656023 + 100156561656024.
It is an arithmetic number, because the mean of its divisors is an integer number (100156561656024).
Almost surely, 2200313123312047 is an apocalyptic number.
200313123312047 is a deficient number, since it is larger than the sum of its proper divisors (1).
200313123312047 is an equidigital number, since it uses as much as digits as its factorization.
200313123312047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 32.
Adding to 200313123312047 its reverse (740213321313002), we get a palindrome (940526444625049).
The spelling of 200313123312047 in words is "two hundred trillion, three hundred thirteen billion, one hundred twenty-three million, three hundred twelve thousand, forty-seven".
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