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200320121300489 is a prime number
BaseRepresentation
bin101101100011000010101001…
…101010111110011000001001
3222021021102020200100001112222
4231203002221222332120021
5202224021102023103424
61550013443203543425
760123436230422621
oct5543025152763011
9867242220301488
10200320121300489
1158912317159503
121a57346b38ab75
1387a114c956248
14376778d1c5881
151825bbce79e5e
hexb630a9abe609

200320121300489 has 2 divisors, whose sum is σ = 200320121300490. Its totient is φ = 200320121300488.

The previous prime is 200320121300323. The next prime is 200320121300491. The reversal of 200320121300489 is 984003121023002.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 174644365534864 + 25675755765625 = 13215308^2 + 5067125^2 .

It is a cyclic number.

It is not a de Polignac number, because 200320121300489 - 216 = 200320121234953 is a prime.

Together with 200320121300491, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (200320121306489) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100160060650244 + 100160060650245.

It is an arithmetic number, because the mean of its divisors is an integer number (100160060650245).

Almost surely, 2200320121300489 is an apocalyptic number.

It is an amenable number.

200320121300489 is a deficient number, since it is larger than the sum of its proper divisors (1).

200320121300489 is an equidigital number, since it uses as much as digits as its factorization.

200320121300489 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 35.

The spelling of 200320121300489 in words is "two hundred trillion, three hundred twenty billion, one hundred twenty-one million, three hundred thousand, four hundred eighty-nine".