Base | Representation |
---|---|
bin | 10010101010000000… |
… | …000100001101000000 |
3 | 1220201001202200222212 |
4 | 102222000010031000 |
5 | 312011143404440 |
6 | 13111431321252 |
7 | 1306261205420 |
oct | 225200041500 |
9 | 56631680885 |
10 | 20032013120 |
11 | 854a604a49 |
12 | 3a70820228 |
13 | 1b73206002 |
14 | d8065a480 |
15 | 7c3991465 |
hex | 4aa004340 |
20032013120 has 224 divisors, whose sum is σ = 58940517120. Its totient is φ = 6330286080.
The previous prime is 20032013011. The next prime is 20032013123. The reversal of 20032013120 is 2131023002.
It is a happy number.
It is a tau number, because it is divible by the number of its divisors (224).
It is a super-4 number, since 4×200320131204 (a number of 42 digits) contains 4444 as substring.
It is a Harshad number since it is a multiple of its sum of digits (14).
It is a junction number, because it is equal to n+sod(n) for n = 20032013095 and 20032013104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20032013123) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1568360 + ... + 1581080.
Almost surely, 220032013120 is an apocalyptic number.
20032013120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 20032013120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29470258560).
20032013120 is an abundant number, since it is smaller than the sum of its proper divisors (38908504000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
20032013120 is a wasteful number, since it uses less digits than its factorization.
20032013120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12801 (or 12791 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 14.
Adding to 20032013120 its reverse (2131023002), we get a palindrome (22163036122).
The spelling of 20032013120 in words is "twenty billion, thirty-two million, thirteen thousand, one hundred twenty".
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