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200323401413140 = 225163229268335791
BaseRepresentation
bin101101100011000101101101…
…001011100111001000010100
3222021021201201021110001012201
4231203011231023213020110
5202224044311230210030
61550015144500054244
760123613430055355
oct5543055513471024
9867251637401181
10200323401413140
115891374a74a705
121a574025994384
1387a15533944c5
1437679c0aa5d2c
151825d10e002ca
hexb6316d2e7214

200323401413140 has 48 divisors (see below), whose sum is σ = 425108295118080. Its totient is φ = 79290005915520.

The previous prime is 200323401413117. The next prime is 200323401413159. The reversal of 200323401413140 is 41314104323002.

It is a happy number.

200323401413140 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 200323401413099 and 200323401413108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 133421356 + ... + 134914435.

It is an arithmetic number, because the mean of its divisors is an integer number (8856422814960).

Almost surely, 2200323401413140 is an apocalyptic number.

200323401413140 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

200323401413140 is an abundant number, since it is smaller than the sum of its proper divisors (224784893704940).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200323401413140 is a wasteful number, since it uses less digits than its factorization.

200323401413140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 268336192 (or 268336190 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 200323401413140 its reverse (41314104323002), we get a palindrome (241637505736142).

The spelling of 200323401413140 in words is "two hundred trillion, three hundred twenty-three billion, four hundred one million, four hundred thirteen thousand, one hundred forty".

Divisors: 1 2 4 5 10 20 163 229 326 458 652 815 916 1145 1630 2290 3260 4580 37327 74654 149308 186635 373270 746540 268335791 536671582 1073343164 1341678955 2683357910 5366715820 43738733933 61448896139 87477467866 122897792278 174954935732 218693669665 245795584556 307244480695 437387339330 614488961390 874774678660 1228977922780 10016170070657 20032340141314 40064680282628 50080850353285 100161700706570 200323401413140