Base | Representation |
---|---|
bin | 11101001001101110101… |
… | …100110011110001011101 |
3 | 21002111220020221212222012 |
4 | 131021232230303301131 |
5 | 230310240333000333 |
6 | 4132150412401005 |
7 | 264506640020015 |
oct | 35115654636135 |
9 | 7074806855865 |
10 | 2003312000093 |
11 | 702666441548 |
12 | 284309176165 |
13 | 116bb0788741 |
14 | 6cd646b0c45 |
15 | 3719db50e48 |
hex | 1d26eb33c5d |
2003312000093 has 2 divisors, whose sum is σ = 2003312000094. Its totient is φ = 2003312000092.
The previous prime is 2003312000057. The next prime is 2003312000153. The reversal of 2003312000093 is 3900002133002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1102107334969 + 901204665124 = 1049813^2 + 949318^2 .
It is a cyclic number.
It is not a de Polignac number, because 2003312000093 - 232 = 1999017032797 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2003318000093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001656000046 + 1001656000047.
It is an arithmetic number, because the mean of its divisors is an integer number (1001656000047).
Almost surely, 22003312000093 is an apocalyptic number.
It is an amenable number.
2003312000093 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003312000093 is an equidigital number, since it uses as much as digits as its factorization.
2003312000093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 2003312000093 its reverse (3900002133002), we get a palindrome (5903314133095).
The spelling of 2003312000093 in words is "two trillion, three billion, three hundred twelve million, ninety-three", and thus it is an aban number.
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