Base | Representation |
---|---|
bin | 101101100011010110011010… |
… | …011110100011000011110111 |
3 | 222021100110000112100201021222 |
4 | 231203112122132203003313 |
5 | 202224343031323033421 |
6 | 1550031312552300555 |
7 | 60125120124653456 |
oct | 5543263236430367 |
9 | 867313015321258 |
10 | 200341341221111 |
11 | 5892031625a992 |
12 | 1a5775b19a175b |
13 | 87a3151cab5ac |
14 | 3768803504b9d |
15 | 1826510d68cab |
hex | b6359a7a30f7 |
200341341221111 has 2 divisors, whose sum is σ = 200341341221112. Its totient is φ = 200341341221110.
The previous prime is 200341341221083. The next prime is 200341341221143. The reversal of 200341341221111 is 111122143143002.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200341341221111 - 238 = 200066463314167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200341341221911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100170670610555 + 100170670610556.
It is an arithmetic number, because the mean of its divisors is an integer number (100170670610556).
Almost surely, 2200341341221111 is an apocalyptic number.
200341341221111 is a deficient number, since it is larger than the sum of its proper divisors (1).
200341341221111 is an equidigital number, since it uses as much as digits as its factorization.
200341341221111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 26.
Adding to 200341341221111 its reverse (111122143143002), we get a palindrome (311463484364113).
The spelling of 200341341221111 in words is "two hundred trillion, three hundred forty-one billion, three hundred forty-one million, two hundred twenty-one thousand, one hundred eleven".
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