Base | Representation |
---|---|
bin | 101101100011011000010110… |
… | …000001111111011110010101 |
3 | 222021100122100222212101102021 |
4 | 231203120112001333132111 |
5 | 202224411303003010401 |
6 | 1550032254401413141 |
7 | 60125222365143553 |
oct | 5543302601773625 |
9 | 867318328771367 |
10 | 200343414110101 |
11 | 5892118a361089 |
12 | 1a577a9003a1b1 |
13 | 87a33c2596422 |
14 | 376895c934bd3 |
15 | 18265d2d282a1 |
hex | b6361607f795 |
200343414110101 has 2 divisors, whose sum is σ = 200343414110102. Its totient is φ = 200343414110100.
The previous prime is 200343414110053. The next prime is 200343414110111. The reversal of 200343414110101 is 101011414343002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 200258018075025 + 85396035076 = 14151255^2 + 292226^2 .
It is a cyclic number.
It is not a de Polignac number, because 200343414110101 - 27 = 200343414109973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200343414110111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100171707055050 + 100171707055051.
It is an arithmetic number, because the mean of its divisors is an integer number (100171707055051).
Almost surely, 2200343414110101 is an apocalyptic number.
It is an amenable number.
200343414110101 is a deficient number, since it is larger than the sum of its proper divisors (1).
200343414110101 is an equidigital number, since it uses as much as digits as its factorization.
200343414110101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 200343414110101 its reverse (101011414343002), we get a palindrome (301354828453103).
The spelling of 200343414110101 in words is "two hundred trillion, three hundred forty-three billion, four hundred fourteen million, one hundred ten thousand, one hundred one".
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