Base | Representation |
---|---|
bin | 10010101010001011… |
… | …110110010111100111 |
3 | 1220201021120122101121 |
4 | 102222023312113213 |
5 | 312012441232213 |
6 | 13112021434411 |
7 | 1306326362425 |
oct | 225213662747 |
9 | 56637518347 |
10 | 20035102183 |
11 | 8551324898 |
12 | 3a7186ba07 |
13 | 1b73a48065 |
14 | d80c22115 |
15 | 7c3da188d |
hex | 4aa2f65e7 |
20035102183 has 2 divisors, whose sum is σ = 20035102184. Its totient is φ = 20035102182.
The previous prime is 20035102111. The next prime is 20035102247. The reversal of 20035102183 is 38120153002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20035102183 - 217 = 20034971111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20035102103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017551091 + 10017551092.
It is an arithmetic number, because the mean of its divisors is an integer number (10017551092).
Almost surely, 220035102183 is an apocalyptic number.
20035102183 is a deficient number, since it is larger than the sum of its proper divisors (1).
20035102183 is an equidigital number, since it uses as much as digits as its factorization.
20035102183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 20035102183 its reverse (38120153002), we get a palindrome (58155255185).
The spelling of 20035102183 in words is "twenty billion, thirty-five million, one hundred two thousand, one hundred eighty-three".
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