Base | Representation |
---|---|
bin | 1011101010011010100… |
… | …1101001011111010101 |
3 | 201011011202000201021121 |
4 | 2322212221221133111 |
5 | 11240321243300232 |
6 | 232013545043541 |
7 | 20322134364661 |
oct | 2724651513725 |
9 | 634152021247 |
10 | 200364431317 |
11 | 77a79552906 |
12 | 329b97865b1 |
13 | 15b81988bcb |
14 | 99aa6678a1 |
15 | 532a45dd97 |
hex | 2ea6a697d5 |
200364431317 has 2 divisors, whose sum is σ = 200364431318. Its totient is φ = 200364431316.
The previous prime is 200364431279. The next prime is 200364431327. The reversal of 200364431317 is 713134463002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 157711442641 + 42652988676 = 397129^2 + 206526^2 .
It is a cyclic number.
It is not a de Polignac number, because 200364431317 - 211 = 200364429269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200364431327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100182215658 + 100182215659.
It is an arithmetic number, because the mean of its divisors is an integer number (100182215659).
Almost surely, 2200364431317 is an apocalyptic number.
It is an amenable number.
200364431317 is a deficient number, since it is larger than the sum of its proper divisors (1).
200364431317 is an equidigital number, since it uses as much as digits as its factorization.
200364431317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36288, while the sum is 34.
Adding to 200364431317 its reverse (713134463002), we get a palindrome (913498894319).
The spelling of 200364431317 in words is "two hundred billion, three hundred sixty-four million, four hundred thirty-one thousand, three hundred seventeen".
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