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200364559697 is a prime number
BaseRepresentation
bin1011101010011010101…
…0001000110101010001
3201011011202021020101102
42322212222020311101
511240321311402242
6232013551514145
720322135441161
oct2724652106521
9634152236342
10200364559697
1177a79630305
12329b9828955
1315b81a02483
1499aa69c5a1
15532a486e32
hex2ea6a88d51

200364559697 has 2 divisors, whose sum is σ = 200364559698. Its totient is φ = 200364559696.

The previous prime is 200364559631. The next prime is 200364559699. The reversal of 200364559697 is 796955463002.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 144965993536 + 55398566161 = 380744^2 + 235369^2 .

It is a cyclic number.

It is not a de Polignac number, because 200364559697 - 226 = 200297450833 is a prime.

Together with 200364559699, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (200364559699) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100182279848 + 100182279849.

It is an arithmetic number, because the mean of its divisors is an integer number (100182279849).

Almost surely, 2200364559697 is an apocalyptic number.

It is an amenable number.

200364559697 is a deficient number, since it is larger than the sum of its proper divisors (1).

200364559697 is an equidigital number, since it uses as much as digits as its factorization.

200364559697 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12247200, while the sum is 56.

Subtracting from 200364559697 its sum of digits (56), we obtain a square (200364559641 = 4476212).

The spelling of 200364559697 in words is "two hundred billion, three hundred sixty-four million, five hundred fifty-nine thousand, six hundred ninety-seven".