Base | Representation |
---|---|
bin | 10010101010101010… |
… | …110011001100001011 |
3 | 1220201211211211221112 |
4 | 102222222303030023 |
5 | 312022030400002 |
6 | 13112511400535 |
7 | 1306455343661 |
oct | 225252631413 |
9 | 56654754845 |
10 | 20043215627 |
11 | 8555966616 |
12 | 3a7452314b |
13 | 1b75629006 |
14 | d81d34c31 |
15 | 7c4955852 |
hex | 4aaab330b |
20043215627 has 2 divisors, whose sum is σ = 20043215628. Its totient is φ = 20043215626.
The previous prime is 20043215461. The next prime is 20043215629. The reversal of 20043215627 is 72651234002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20043215627 - 210 = 20043214603 is a prime.
It is a super-3 number, since 3×200432156273 (a number of 32 digits) contains 333 as substring.
Together with 20043215629, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 20043215593 and 20043215602.
It is not a weakly prime, because it can be changed into another prime (20043215629) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10021607813 + 10021607814.
It is an arithmetic number, because the mean of its divisors is an integer number (10021607814).
Almost surely, 220043215627 is an apocalyptic number.
20043215627 is a deficient number, since it is larger than the sum of its proper divisors (1).
20043215627 is an equidigital number, since it uses as much as digits as its factorization.
20043215627 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 32.
Adding to 20043215627 its reverse (72651234002), we get a palindrome (92694449629).
The spelling of 20043215627 in words is "twenty billion, forty-three million, two hundred fifteen thousand, six hundred twenty-seven".
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