Base | Representation |
---|---|
bin | 1011101010101011001… |
… | …1100000100100101111 |
3 | 201011100121011112011221 |
4 | 2322222303200210233 |
5 | 11240442114000403 |
6 | 232024514524211 |
7 | 20323641644602 |
oct | 2725263404457 |
9 | 634317145157 |
10 | 200434125103 |
11 | 78004924883 |
12 | 32a18b96667 |
13 | 15b9324b234 |
14 | 99b5a0a339 |
15 | 5331628dbd |
hex | 2eaace092f |
200434125103 has 2 divisors, whose sum is σ = 200434125104. Its totient is φ = 200434125102.
The previous prime is 200434125049. The next prime is 200434125113. The reversal of 200434125103 is 301521434002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200434125103 - 229 = 199897254191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200434125113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100217062551 + 100217062552.
It is an arithmetic number, because the mean of its divisors is an integer number (100217062552).
Almost surely, 2200434125103 is an apocalyptic number.
200434125103 is a deficient number, since it is larger than the sum of its proper divisors (1).
200434125103 is an equidigital number, since it uses as much as digits as its factorization.
200434125103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 200434125103 its reverse (301521434002), we get a palindrome (501955559105).
The spelling of 200434125103 in words is "two hundred billion, four hundred thirty-four million, one hundred twenty-five thousand, one hundred three".
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