Base | Representation |
---|---|
bin | 101101100100111011110110… |
… | …001100111111111101010111 |
3 | 222021201212010212112202000202 |
4 | 231210323312030333331113 |
5 | 202233134110100312114 |
6 | 1550153324153531115 |
7 | 60136024110632543 |
oct | 5544736614777527 |
9 | 867655125482022 |
10 | 200450254307159 |
11 | 589625259134aa |
12 | 1a594728713a9b |
13 | 87b04bb259c3c |
14 | 376dbb61d4a23 |
15 | 1829287812cde |
hex | b64ef633ff57 |
200450254307159 has 2 divisors, whose sum is σ = 200450254307160. Its totient is φ = 200450254307158.
The previous prime is 200450254307123. The next prime is 200450254307189. The reversal of 200450254307159 is 951703452054002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200450254307159 is a prime.
It is a super-2 number, since 2×2004502543071592 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200450254307189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100225127153579 + 100225127153580.
It is an arithmetic number, because the mean of its divisors is an integer number (100225127153580).
Almost surely, 2200450254307159 is an apocalyptic number.
200450254307159 is a deficient number, since it is larger than the sum of its proper divisors (1).
200450254307159 is an equidigital number, since it uses as much as digits as its factorization.
200450254307159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512000, while the sum is 47.
The spelling of 200450254307159 in words is "two hundred trillion, four hundred fifty billion, two hundred fifty-four million, three hundred seven thousand, one hundred fifty-nine".
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