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200450254307159 is a prime number
BaseRepresentation
bin101101100100111011110110…
…001100111111111101010111
3222021201212010212112202000202
4231210323312030333331113
5202233134110100312114
61550153324153531115
760136024110632543
oct5544736614777527
9867655125482022
10200450254307159
11589625259134aa
121a594728713a9b
1387b04bb259c3c
14376dbb61d4a23
151829287812cde
hexb64ef633ff57

200450254307159 has 2 divisors, whose sum is σ = 200450254307160. Its totient is φ = 200450254307158.

The previous prime is 200450254307123. The next prime is 200450254307189. The reversal of 200450254307159 is 951703452054002.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200450254307159 is a prime.

It is a super-2 number, since 2×2004502543071592 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200450254307189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100225127153579 + 100225127153580.

It is an arithmetic number, because the mean of its divisors is an integer number (100225127153580).

Almost surely, 2200450254307159 is an apocalyptic number.

200450254307159 is a deficient number, since it is larger than the sum of its proper divisors (1).

200450254307159 is an equidigital number, since it uses as much as digits as its factorization.

200450254307159 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512000, while the sum is 47.

The spelling of 200450254307159 in words is "two hundred trillion, four hundred fifty billion, two hundred fifty-four million, three hundred seven thousand, one hundred fifty-nine".