Base | Representation |
---|---|
bin | 101101101100111100111110… |
… | …010100110001111101011011 |
3 | 222100200112021121221000121022 |
4 | 231230330332110301331123 |
5 | 202321200444322323121 |
6 | 1551254404043233055 |
7 | 60223600420032104 |
oct | 5554747624617533 |
9 | 870615247830538 |
10 | 201001220120411 |
11 | 59055158737817 |
12 | 1a663471b1878b |
13 | 8820445275059 |
14 | 378c7221173ab |
15 | 18387829b7aab |
hex | b6cf3e531f5b |
201001220120411 has 2 divisors, whose sum is σ = 201001220120412. Its totient is φ = 201001220120410.
The previous prime is 201001220120399. The next prime is 201001220120413. The reversal of 201001220120411 is 114021022100102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201001220120411 is a prime.
Together with 201001220120413, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 201001220120411.
It is not a weakly prime, because it can be changed into another prime (201001220120413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100500610060205 + 100500610060206.
It is an arithmetic number, because the mean of its divisors is an integer number (100500610060206).
Almost surely, 2201001220120411 is an apocalyptic number.
201001220120411 is a deficient number, since it is larger than the sum of its proper divisors (1).
201001220120411 is an equidigital number, since it uses as much as digits as its factorization.
201001220120411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 201001220120411 its reverse (114021022100102), we get a palindrome (315022242220513).
The spelling of 201001220120411 in words is "two hundred one trillion, one billion, two hundred twenty million, one hundred twenty thousand, four hundred eleven".
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