2011000001207 has 2 divisors, whose sum is σ = 2011000001208. Its totient is φ = 2011000001206.

The previous prime is 2011000001173. The next prime is 2011000001221. The reversal of 2011000001207 is 7021000001102.

It is an a-pointer prime, because the next prime (2011000001221) can be obtained adding 2011000001207 to its sum of digits (14).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2011000001207 - 2¹⁰ = 2011000000183 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2011000001191 and 2011000001200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2011000001237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005500000603 + 1005500000604.

It is an arithmetic number, because the mean of its divisors is an integer number (1005500000604).

Almost surely, 2^{2011000001207} is an apocalyptic number.

2011000001207 is a deficient number, since it is larger than the sum of its proper divisors (1).

2011000001207 is an equidigital number, since it uses as much as digits as its factorization.

2011000001207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 14.

Adding to 2011000001207 its reverse (7021000001102), we get a palindrome (9032000002309).

The spelling of 2011000001207 in words is "two trillion, eleven billion, one thousand, two hundred seven".