Base | Representation |
---|---|
bin | 11101010000111000111… |
… | …100001101111001100101 |
3 | 21010020202001021221221221 |
4 | 131100320330031321211 |
5 | 230422012000113242 |
6 | 4135501325140341 |
7 | 265201311666112 |
oct | 35207074157145 |
9 | 7106661257857 |
10 | 2011000004197 |
11 | 705951091848 |
12 | 2858b39ba6b1 |
13 | 1178374908b2 |
14 | 6d493761909 |
15 | 3749da6d167 |
hex | 1d438f0de65 |
2011000004197 has 2 divisors, whose sum is σ = 2011000004198. Its totient is φ = 2011000004196.
The previous prime is 2011000004183. The next prime is 2011000004219. The reversal of 2011000004197 is 7914000001102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1899327741921 + 111672262276 = 1378161^2 + 334174^2 .
It is a cyclic number.
It is not a de Polignac number, because 2011000004197 - 227 = 2010865786469 is a prime.
It is a super-2 number, since 2×20110000041972 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011000004597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005500002098 + 1005500002099.
It is an arithmetic number, because the mean of its divisors is an integer number (1005500002099).
Almost surely, 22011000004197 is an apocalyptic number.
It is an amenable number.
2011000004197 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011000004197 is an equidigital number, since it uses as much as digits as its factorization.
2011000004197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 2011000004197 its reverse (7914000001102), we get a palindrome (9925000005299).
The spelling of 2011000004197 in words is "two trillion, eleven billion, four thousand, one hundred ninety-seven".
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